NECO 2021 Chemistry Expo Questions and Answers – June/July Exam

NECO 2021 Accounting Expo

NECO 2021 Chemistry Expo Questions and Answers – June/July Exam

Obj!

 

1EECBBAEBBB

11DDDBEAEABB

21DBECCDAAAB

31BADCBACDAC

41CECCEADBDC

51CEBEEDDBAE

 

Completed!.

====================================

 

 

Chemistry-THEORY

(4a)

(i)Enthalpy of combustion can be defined as the amount of heat evolved when one mole of a substance burns in air or oxygen

 

(ii) Isomerism can be defined as a phenomenon in which organic compounds are having the same molecular formula but different structural formula

 

(4bi)

NO2 – Acidic oxide

CO – Neutral oxide

Fe2O3 – Basic oxide

Al2O3 – Amphoteric oxide

 

(4bii)

(i)Nitrous oxide

(ii)Carbon (iv) oxide

 

(4c)

(i) Fractional distillation of liquid air

 

(ii) 2KNO3 —–> 2KNO2(s) + O2(g)

 

(NH)CO3(s) ——>2NH3(g) + CO2(g) + H2O(g)

 

(iii) No. of molecules = 4/16 × 6.02 × 10²³

= 1.5 × 10²³

 

(4di)

(i)Sodium

(ii)Potassium

 

(4dii)

(i)Carbon (iv) oxide

(ii)Carbon

 

(4diii)

(i)Hydration

(ii)Oxidation

====================================

 

(5ai)

Gay Lussac’s states that when gaese react, they do so in volume which bear a simple whole number ratio to one another and to the volume of their products.

RECOMMEND POST -  NECO 2021 Agric Expo Questions and Answers – June/July Exam

 

(5aii)

2CO + O2 —-> 2CO2

2 1 2

100cm³ 70cm³ 100cm³

 

Total volume = 100+70+100 = 270cm³

 

(5bi)

(i)It is used in the production of other chemical substances

(ii)It is used as a drying or dehydrating agent

 

(5bii)

(i) ZnCO3 —–> ZnO + CO2

 

->Conditions<-

– High temperature

– High pressure

 

(ii) ZnO + H2SO4 —-> ZnSO4 + H2

 

->Conditions<-

– Catalyst

– Surface area

 

(5biii)

(i) Crystallization method

(ii) By heating the ZnSO4 with an alkali metal carbonate

 

(5c)

(i) This is due to the presence of extra electrons not used for bonding graphite

(ii) This is because sodium salts are soluble and double decomposition is used for the production of insoluble salts

(iii) It is an alkali substance ie possesses basic properties

 

(5di)

(i)Bitumen coal

(ii)Peat coal

 

(5dii)

Fractional distillation

====================================

 

(2ai)

(i)Molecules of gases are in constant random motion

(ii)The collision of gases is perfectly elastic

RECOMMEND POST -  NECO 2021 Literature-In-English Expo Questions/Answers | June/July Exam

(iii)An increase in temperature leads to an increase in the average kinetic energy of the molecules of gases

 

(2aii)

(i)They both turn blue litmus paper red

(ii)They both dissolve in water to produce an acid

 

(2aiii)

Copper<Iron<Aluminium<Magnesium

 

(2aiv)

Copper

 

(2bi)

Activation energy can be defined as the minimum energy required for a reaction to occur.

 

(2bii)

Catalyst lowers activation energy

 

(2biii)

Nikel

 

(2biv)

(i)Sodium trioxocarbonate (iv)

(ii)Hydrogen gas

 

(2ci)

(i)It reacts with metals to liberate hydrogen

(ii)It reacts with base to produce salt and water only

 

(2cii)

(i) 2KI + 2Cl2 —-> 2Kl2 + I2

 

(ii) 2Zn + Cl2 —–> 2ZnCl

 

(2ciii)

Cl2

 

(2civ)

Covalent bond

 

(2d)

(i) Butane

(ii) Propene

(iii) Ethanol

(iv) Ethyne

====================================

 

(1ai)

(i) Base has bitter taste

(ii) Base is soapy to touch

(iii) Base turns litmus paper blue

 

(1aii)

The steps involved are:

(i)Shift conversion

(ii)Removal of carbon (iv) oxide

RECOMMEND POST -  NECO 2021 Economics Expo Questions and Answers – June/July Exam

(iii)Steam reforming

 

(1aiii)

Cracking is the process by which heavier hydrocarbon molecule is splitted into two or more lighter molecules

 

(1aiv)

Thermal cracking

 

(1bi)

P ion = 1s²2s²2p⁶

 

(1bii)

Formula of chloride is Pcl2

 

(1biii)

Reducing agent

This is because it undergoes oxidation by losing electrons

 

(1ci)

Electron affinity is the energy released when a gaseous atom gains an electron to form a gaseous negative ion.

 

(1cii)

This is because it has lone pairs of electrons

 

(1di)

(i) By adding a catalyst

 

(ii) FeS(s) + 2HCl(g) —–> FeCl(g) + H2S(s)

 

Xg = ?

No. of FeCl2 = 127g/mole

No. of FeS= 88g/mole

 

Mole = Mass/ No. of Mass = 3.2/127 = 0.025mole of FeCl2

 

By comparison,

1 mole of FeS = 1 mole of FeCl2

X moles of FeS = 0.025 of FeCl2

X = 0.025mole of FeS

 

Recall,

Mass = Mole * molar mass

Mass = 0.025*88

Mass = 2.2g of FeS

X = 2.2g

 

(1dii)

(i)Chlorofluorocarbons

(ii)Ammonia

====================================

 

Completed!. We Remain The baddest

Be the first to comment

Leave a Reply

Your email address will not be published.


*